Respuesta :
Answer:
b = [tex]\frac{5a-2}{a-1}[/tex]
Step-by-step explanation:
Given
a = [tex]\frac{b-2}{b-5}[/tex] ← multiply both sides by (b - 5)
a(b - 5) = b - 2 ← distribute left side
ab - 5a = b - 2 ← subtract b from both sides
ab - b - 5a = - 2 ← add 5a to both sides
ab - b = 5a - 2 ← factor out b from each term on the left side
b(a - 1) = 5a - 2 ← divide both sides by (a - 1)
b = [tex]\frac{5a-2}{a-1}[/tex]
Answer:
b = ab -5a + 2
Step-by-step explanation:
Given a = b-2/b-5
Cross multiply
a(b-5) = b-2
Using the distributive property we have
axb -ax5 = b-2
ab -5a = b -2
Add 2 to both sides
ab - 5a +2 = b -2+2
ab - 5a + 2 = b
Therefore b = ab -5a + 2