Respuesta :
x amount invested at 10%
.10x + .08(10000-x) = $940
x = 140/.02 = 7000, invested at 10%. 300010000-7000 at 8%
.10x + .08(10000-x) = $940
x = 140/.02 = 7000, invested at 10%. 300010000-7000 at 8%
The amount invested at 10% is $7000 and the amount invested at 8% is $3000.
How to find the invested amount?
Let consider x amount invested at 10%
0.10x + 0.08(10000-x) = $940
0.10x + 800 - 0.08x = $940
x = 140/.02
x = 7000, invested at 10%.
Let consider y amount invested at 8%
y = 10000-7000
y = 3000 at 8%
Hence, the amount invested at 10% is $7000 and the amount invested at 8% is $3000.
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