Answer:
1 liter
Explanation:
Molality is calculated by dividing the moles of the solute with kilograms of solvent(unit: moles / L). The molecular weight for sucrose is 343.2 g/mol and the density of water is 1kg/L. Then the molality of the solution right now is:
molality = moles of solute / kg of solvent
molality = 35g / (342.3g/mol) / 1L*1kg/L= 0.102 moles / 1 kg= 0.102 m
You want to make the molality into half (0.056 m) with the same number of solute(0.102 moles) but adding more solvent. Then the number of water you need to add is
molality = moles of solute / kg of solvent
0.056 m= 0.102 moles/ solvent
solvent= (0.056 moles/ kg)/ 0.102 moles= 2kg
Two kilograms of water in liters will be: 2kg / (1kg/L)= 2L
The solution already has 1L of water. Liters of water you need to add will be: 2L - 1L = 1L
