A quantity with an initial value of 9100 grows continuously at a rate of 0.85% per hour. What is the value of the quantity after 22 hours, to the nearest hundredth?

Respuesta :

Answer:

[tex]10,962,54[/tex]

Step-by-step explanation:

we know that

The equation of a exponential growth is equal to

[tex]y=a(1+r)^x[/tex]

where

a is the initial value  

r is the rate of growth

x is the time in hours

y is the value of the quantity

we have

[tex]a=9,100\\r=0.85\%=0.85/100=0.0085[/tex]

substitute

[tex]y=9,100(1+0.0085)^x[/tex]

[tex]y=9,100(1..0085)^x[/tex]

For x=22 hours

substitute

[tex]y=9,100(1..0085)^{22} =10,962,54[/tex]

Answer:17050289.61

Step-by-step explanation: