Answer:
[tex]f(x)=x^4-9x^2-50x-150[/tex]
Step-by-step explanation:
Let f(x) be the polynomial function of minimum degree with real coefficients whose zeros are 5, -3, and -1 + 3i be f(x).
By the complex conjugate property of polynomials, -1-3i is also a root of this polynomial.
Therefore the polynomial in factored form is [tex]f(x)=(x-5)(x+3)(x-(-1+3i))(x-(-1+3i))[/tex]
We expand to get:[tex]f(x)=(x^2-2x-15)(x^2+2x+10)[/tex]
We expand further to get:\
[tex]f(x)=x^4-9x^2-50x-150[/tex]