la19870
la19870
13-10-2014
Mathematics
contestada
(9x-3 1/8)- (7x+1 3/8)
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luana
luana
13-10-2014
[tex]*\\(9x-3\frac{1}{8})-(7x+1\frac{3}{8})=\ \ \ |Omit\ the\ brackets\\\\ (9x-3\frac{1}{8})-(7x+1\frac{3}{8})=9x-3\frac{1}{8}-7x-1\frac{3}{8}=\ \ \ \ \ |add\ similar\ factors\\\\ \boxed{2x-4\frac{1}{2}}[/tex]
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