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An ice cube with mass mi=30 g and temperature T=0℃ completely melts in a cup of water. The mass of the water in the cup is mw=275 g and its initial temperature, before dropping the ice cube in it, is Tw=29℃. Calculate the temperature of the water in the cup at the instant the ice cube has completely melted. The specific heat capacity of water is cw=4.186 J/(g℃) and the latent heat of fusion of ice is Lf=334 J/g.

Respuesta :

Answer:

When ice melts down completely then the temperature of water must be 20.3 degree C

Explanation:

As per energy conservation law we know that thermal energy given by the water = thermal energy absorbed by ice which will help it to melt down

So here when ice melts down completely then we have

[tex]Q = mL[/tex]

so we have

[tex]Q = 30 \times 334[/tex]

[tex]Q = 10020 J[/tex]

now we have

[tex]Q_{water} = ms\Delta T[/tex]

[tex]10020 = 275 (4.186) (29 - T)[/tex]

[tex]8.70 = 29 - T[/tex]

[tex]T = 20.3 degree C[/tex]

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