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A patio swing is suspended by two springs, each of which has a force constant of 450 N/m equivalent to a single spring forest constant of 900 N/m. Find the mass of a person sitting on the swing oscillating up and down out of 0.560 Hz.

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MathPhys

Explanation:

Frequency of a spring is:

2πf = √(k/m)

Solving for m:

(2πf)² = k / m

m = k / (2πf)²

Plugging in values:

m = (900 N/m) / (2π (0.560 Hz))²

m = 72.7 kg

Round as needed.

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