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14-07-2016
Mathematics

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What values of x and y satisfy −133x−2y=7 and 3x+25y=5 simultaneously?

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Edufirst Edufirst

26-07-2016

1) -133x - 2y = 7

2) 3x + 25 y = 5

Multiply 1) by 25 and 2) by 2, then

1a) - 3325x - 50y = 175
2a) 6x + 50y = 10

Add the 1a) and 2a)

3) -3319x = 185

x = - 185 / 3319 = -0.056

from 1) y = (-133(x) -7) /(2) = [-133(-185/3319) -7]/2 =0.207

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