suppose $5,000 is invested in an account at an annual interest rate of 2.7% compounded continuously. how long (to the nearest tenth of a year) will it take the investment to double in size?

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The basic equation for continuous compounding is as follows:
[tex]A=Pe^{rt}[/tex]
Plugging in the given values gives:
[tex]10000=5000e^{0.027t}[/tex]
Dividing both sides by 5000, we get:
[tex]2=e^{0.027t}[/tex]
Take natural logs of each side:
[tex]ln\ 2=0.027t[/tex]
from which we find that t = 25.67 years.