Answer:
The value of [tex]g(f(-1))=\frac{1}{2}[/tex]
Step-by-step explanation:
Given : [tex]f(x)=x^2[/tex] and [tex]g(x)=\frac{1}{2}x^3[/tex]
To find : The value of [tex]g(f(-1))[/tex]?
Solution :
First we find the function g(f(x)),
Which means substitute the value of f(x) in g(x)
[tex]g(f(x))=\frac{1}{2}(x^2)^3[/tex]
[tex]g(f(x))=\frac{1}{2}(x^6)[/tex]
Now, we put the value of x=-1
[tex]g(f(-1))=\frac{1}{2}(-1^6)[/tex]
[tex]g(f(-1))=\frac{1}{2}(1)[/tex]
[tex]g(f(-1))=\frac{1}{2}[/tex]
Therefore, The value of [tex]g(f(-1))=\frac{1}{2}[/tex]
