Respuesta :

dalendrk
[tex]The\ equation\ of\ the\ circle:\\(x-a)^2+(y-b)^2=r^2\\where\\(a;\ b)-the\ center\\r-the\ radius\\-----------------\\the\ center:(5;-4)\\the\ radius\ is\ equal\ the\ distance\ between\ (5;-4)\ and\ (-3;\ 2)\\------------------\\A(x_1;\ y_!);\ B(x_2;\ y_2)\\the\ distance\ between\ A\ and\ B\\d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\------------------\\r=\sqrt{(-3-5)^2+(2-(-4))^2}=\sqrt{(-8)^2+6^2}=\sqrt{64+36}\\=\sqrt{100}=10\\-----------------\\Answer:\\\boxed{(x-5)^2+(y+4)^2=10^2}[/tex]

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