Respuesta :

P(2 aces) = (1/13)^2 
P(2 kings) = (1/13)^2 

P(king and ace) = 8C2/52C2 - 2(1/13)^2 = 0.0152 

Answer:

[tex]\frac{1}{169}[/tex]

Step-by-step explanation:

Total cards = 52

Total ace = 4

So probability of getting ace on first draw = [tex]\frac{4}{52}[/tex]

Now the card is replaced .

So, Total cards = 52

Total kings = 4

So probability of getting kings on second draw = [tex]\frac{4}{52}[/tex]

So,  the probability of choosing a king and an ace:

=  [tex]\frac{4}{52} \times \frac{4}{52}[/tex]

=  [tex]\frac{1}{169}[/tex]

Hence the probability of choosing a king and an ace is  [tex]\frac{1}{169}[/tex]