Respuesta :
P(2 aces) = (1/13)^2
P(2 kings) = (1/13)^2
P(king and ace) = 8C2/52C2 - 2(1/13)^2 = 0.0152
P(2 kings) = (1/13)^2
P(king and ace) = 8C2/52C2 - 2(1/13)^2 = 0.0152
Answer:
[tex]\frac{1}{169}[/tex]
Step-by-step explanation:
Total cards = 52
Total ace = 4
So probability of getting ace on first draw = [tex]\frac{4}{52}[/tex]
Now the card is replaced .
So, Total cards = 52
Total kings = 4
So probability of getting kings on second draw = [tex]\frac{4}{52}[/tex]
So, the probability of choosing a king and an ace:
= [tex]\frac{4}{52} \times \frac{4}{52}[/tex]
= [tex]\frac{1}{169}[/tex]
Hence the probability of choosing a king and an ace is [tex]\frac{1}{169}[/tex]