Respuesta :
so r1/4 = 13.5/r2 = r2/r1
r1*r2 = 54 ----------eqn(1)
r2^2 = 13.5r1--------eqn(2)
from(2) r1 = r2^2/13.5
substituting this in eqn(1)
r2^3/13.5 = 54
r2^3 = 54*13.5 = 729
r2 = 9
r1 = 81/13.5 = 6
so two geometric means between 4, 13.5 are 6 and 9
r1*r2 = 54 ----------eqn(1)
r2^2 = 13.5r1--------eqn(2)
from(2) r1 = r2^2/13.5
substituting this in eqn(1)
r2^3/13.5 = 54
r2^3 = 54*13.5 = 729
r2 = 9
r1 = 81/13.5 = 6
so two geometric means between 4, 13.5 are 6 and 9