Respuesta :
Arithmetic, nth = a + (n - 1)d, common difference, d = 5
a₁₂ = a + (12 -1)d = 63
a + 11d = 63
a + 11*5 = 63
a = 63 - 11*5
a = 63 - 55
a = 8
So the nth term = a + (n - 1)d = 8 + (n - 1)5
8 + 5*(n - 1)
8 + 5n - 5
8 - 5 + 5n
3 + 5n
So nth term = 3 + 5n
a₁₂ = a + (12 -1)d = 63
a + 11d = 63
a + 11*5 = 63
a = 63 - 11*5
a = 63 - 55
a = 8
So the nth term = a + (n - 1)d = 8 + (n - 1)5
8 + 5*(n - 1)
8 + 5n - 5
8 - 5 + 5n
3 + 5n
So nth term = 3 + 5n