Our solution has 85.5 g of solute in 100 g of solution:
[tex]155\ g\ solution\cdot \frac{85.5\ g\ NaCl}{100\ g\ solution} = 132.52\ g\ NaCl[/tex]
The molecular mass of NaCl is: 23 + 35.5 = 58.5 g/mol.
[tex]132.52\ g\ NaCl\cdot \frac{1\ mol}{58.5\ g} = \bf 2.26\ mol\ NaCl[/tex]