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What is the minimum number of moles of potassium permanganate that would be required to completely oxidize 1.0 moles of benzaldehyde?

Respuesta :

Willchemistry
Mole ratio :

5 C₆H₆CHO + 2 KMnO₄ + 6 H⁺ = 5 C₆H₆COOH + 2 Mn²⁺ + 3 H₂O + 2 K⁺

5 moles C₆H₆CHO ------------------ 2 moles KMnO₄
1.0 moles C₆H₆CHO ---------------- ( moles of KMnO₄ )

moles of KMnO₄ = 1.0 x 2 / 5

moles of KMnO₄ = 2 / 5

= 0.40 moles of KMnO4

hope this helps!


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