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An air compressor used with a paint sprayer does 64.0 J of work pumping air into a tank. Warmed by the process, the air in the tank gives off 37.0 J of energy to its surroundings. What is the change in the internal energy of the air in the tank as a result of the two processes?

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lublana

Answer:

27 J

Explanation:

We are given that

Work done,w=64 J

Energy,Q=-37 J

We have to find the change in the internal energy of the air in the  tank.

By First law of thermodynamics

[tex]\Delta U=q+w[/tex]

Using the formula

[tex]\Delta U=-37+64[/tex]

[tex]\Delta U=27J[/tex]

Hence, the change in the internal energy of the air in the tank=27 J

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