Answer:
The Enthalpy of the reaction ΔH = 0.945 [tex]\frac{KJ}{mole}[/tex]
Explanation:
Given data
Mass = 0.15 kg
Change in temperature = 24 - 21 = 3 °c
Enthalpy of the solution is given by
ΔH = m [tex]C_{p}[/tex] ΔT
ΔH = 0.15 × 4.2 × 3
ΔH = 1.89 KJ
Enthalpy change per mole
ΔH = [tex]\frac{1.89}{2}[/tex]
ΔH = 0.945 [tex]\frac{KJ}{mole}[/tex]
Therefore the Enthalpy of the reaction ΔH = 0.945 [tex]\frac{KJ}{mole}[/tex]
