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A balloon has a volume of 2.29 liters at a pressure of 100.0 kPa. If the pressure of the balloon is decreased to 83.5 kPa, what will be the new volume of the balloon?

Respuesta :

olatunbosunadeoke

Answer: 2.74 litres

Explanation:

Given that,

Original pressure of balloon (P1) = 100.0 kPa

Original volume of balloon (V1) = 2.29 litres

New pressure of balloon (P2) = 83.5 kPa

New volume of balloon (V2) = ?

Since pressure and volume are given while temperature is held constant, apply the formula for Boyle's law

P1V1 = P2V2

100 kPa x 2.29 L = 83.5 kPa x V2

229 kPa•L = 83.5 kPa•V2

Divide both sides by 83.5 kPa

229 kPa•L/83.5 kPa = 83.5 kPa•V2/ 83.5 kPa

2.74 L = V2

Thus, the new volume of the balloon is 2.74 litres

Ritmeks

The new volume of the balloon is 1.9 liters

The parameters given in the question are;

pressure 1= 100 kPa

pressure2= 83.5 kPa

Volume 1= 2.29 liters

P1/V1= P2/V2

100/2.29= 83.5/V2

Cross multiply

100 V2= 83.5 × 2.29

100 V2= 191.215

V2= 191.215/100

V2= 1.91 liters

Hence the new volume is 1.91 liters

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https://brainly.com/question/15716958?referrer=searchResults

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