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Liquid nitrogen which normally has a boiling point of 77K is commonly used to cool substances to low temperatures. How much energy must be removed from 1.0 KG of gaseous nitrogen at 77K for it to completely liquefy?

Respuesta :

Answer:

99.74 kJ

Explanation:

The molar latent heat of vaporization of nitrogen gas is 2.7928 kJ / mole

molecular weight of nitrogen is 28 gm .

So 28 gram of nitrogen will release 2792.8 J of heat on liquefaction

1 gram of nitrogen   will release 2792.8 /28 J of heat

1 kg of nitrogen will release (2792.8 /28)kJ of heat.

= 99.74 kJ of heat

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