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15-04-2020
Mathematics

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Farmer bob was counting his cows and chickens and saw that there was 54 legs all together if he had 20 cows and chickens how many of each did he have?

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15-04-2020

Answer: <3

7 cows and 13 chickens

Step-by-step explanation:

System of Equations:

x = cows

y = chickens

x + y =20 --> y = -x + 20

4x + 2y = 54

substitute:

4x + 2(-x + 20) = 54

4x - 2x + 40 = 54

2x = 14

x = 7 cows

Now we plug in x to get y.

7 + y = 20

y = 13 chickens

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