By applying the concepts of trigonometric functions, the value of the cosine of an angle θ given that (x, y) = (- 2, - 3) is equal to - 2√13 /13.
In this problem we have a vector whose beginning is set in the origin, whose cosine is represented by the following definition:
[tex]\cos \theta = \frac{x}{\sqrt{x^{2}+y^{2}}}[/tex] (1)
If we know that x = - 2 and y = - 3, then the cosine is:
cos θ = - 2 /√13 = - 2√13 /13
By applying the concepts of trigonometric functions, the value of the cosine of an angle θ given that (x, y) = (- 2, - 3) is equal to - 2√13 /13.
To learn more on trigonometric functions: https://brainly.com/question/6904750
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