The question is incomplete, the complete question is:
A hand truck is used to move two barrels each weighing 80 lb. Neglecting the weight of the hand truck, find the vertical force P needed to maintain equilibrium when alpha = 40.
A) Would it be easier to run x along the horizontal axis of the page or along the axis of the hand truck when it comes to summing the moments?
B) List all loads that occur on the diagram (including reaction)
C) Find P with the given alpha to maintain equilibrium
Answer:
It would be easier to run x axis along the axis of the hard truck in the sense that we do not need to change the perpendicular distance between the center of gravity in the original direction.
P=8.0407
Explanation:
From the above information
- 32 × cos α
- 80 × sin α
-8cosα
P to maintain equilibrium
W=mg= 80lb
x1= (20sinα - 8cosα) inch
x2=(32cosα - 20sinα) inch
b=64cosα inch
Given α=40
x1= 12.855 - 6.128= 6.727 inch
x2=24.51 - 12.855= 11.655 inch
b=49.03 inch
When we take the moment about B, we have
P(b) - W(x2) + W(x1) =0
P(49.03) - 80(11.655)+ 80(6.727)
49.03p= 932.4 - 538.16
P= 8.0407
