Answer:
Acceleration of the object on mars, [tex]a=3.75\ m/s^2[/tex]
Explanation:
It is given that,
The weight of an object on Earth is, W = 350 newtons.
The acceleration due to gravity on the Earth, [tex]g=9.8\ m/s^2[/tex]
Let m is the mass of the object. Weight of an object is equal to the product of mass and acceleration due to gravity.
[tex]m=\dfrac{W}{g}[/tex]
[tex]m=\dfrac{350\ N}{9.8\ m/s^2}[/tex]
m = 35.71 Kg
The weight of the object on mars, W' = 134 N
Mass of an object is the amount of matter contained it. It remains the same at every location. So,
[tex]a=\dfrac{W'}{m}[/tex]
[tex]a=\dfrac{134\ N}{35.71\ kg}[/tex]
[tex]a=3.75\ m/s^2[/tex]
So, the acceleration of the object on the surface of mars is [tex]3.75\ m/s^2[/tex]. Hence, this is the required solution.
