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The pressure observed after reaction with Zn metal and HCl should be corrected to subtract the pressure due to water vapor present at the final system temperature (22°C). Write down the corrected pressure P:________

Respuesta :

Answer:

The correct answer to the following question will be "Pressure = 18394.168 torr".

Explanation:

The reaction is:

Zn + 2HCl ⇒ ZnCl2 + H2

Let,

H2 = 1 mole

Volume, V = 1 L

As we know,

[tex]Pressure(P) = \frac{nRT}{V}[/tex]

On putting the values in the above formula, we get

[tex]P=\frac{1\times 0.0821\times 295.15}{1}[/tex]

[tex]P=24.2318 \ atm[/tex]

[tex]P=24.2318\times 760[/tex]

[tex]P=18416.168 \ torr[/tex]

Now,

[tex]P \ original = P \ obtained-PH2O[/tex]

[tex]P \ original=18416.168-22[/tex]

[tex]P \ original=18394.168 \ torr[/tex]

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