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A geneticist collected data of a population of mice. Of the 50 mice, 12 were homozygous black (BB), 24 were heterozygous black (Bb), and 14 were brown (bb).

What are the allele frequencies for the (B) and (b) alleles in this population?

A. B = 0.32; b = 0.68
B. B = 0.36; b = 0.64
C. B = 0.48; b = 0.52
D. B = 0.45; b = 0.55

Respuesta :

Answer:

option C: B = 0.48; b = 0.52

Explanation:

Of the 50 mice, 12 were homozygous black (BB), 24 were heterozygous black (Bb), and 14 were brown (bb).

BB        Bb       bb    Total

12     +  24    +  14   =  50

the formular for alleleic frequency (p) is (BB+ Bb/2) / total,

q = (bb + Bb/2) / total

Allelic frequecy of B (p) is (12 + 24/2) /50 = 12 + 12 = 24/50 = 0.48

Allelic frequency of b (q) is (14 + 24/2) / 50= 14 + 12 = 26/50 = 0.52

check p + q = 1; 0.48 + 0.52 = 1

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