Respuesta :
Answer:
There are 90 different ways
Step-by-step explanation:
We can apply factorials to help solve this equation.
Just to review, 4!= 4x3x2x1
To solve this problem, we need to use factorials but only a portion of it.
Since there are only 2 roles, we only have to go down two numbers
For captain, there are 10 players available,
But for co captain, there are 9, because the captain can't also be the co captain
So the result is 10x9
We don't have to go further since there are no more further roles to occupy
10x9=90
There are 90 different ways
Answer:
45 if two co-captains or 90 if captain and co-captain are two DISTINCT roles.
Step-by-step explanation:
METHOD ONE
Label each player (either a through j OR 1 - 10).
List combinations:
- a b
- a c
- a d
- a e
- a f
- a g
- a h
- a i
- a j
- b c (not "b a" because that would be the same as #1)
- b d
- b e
- b f
- b g
- b h
- b i
- b j
- c d (not "c a" or "c b" because those would be duplicates)
- c e
- c f
- c g
- c h
- c i
- c j
- d e
- d f
- d g
- d h
- d i
- d j
- e f
- e g
- e h
- e i
- e j
- f g
- f h
- f i
- f j
- g h
- g i
- g j
- h i
- h j
- j i
METHOD 2
use formula