Cheryl has now been lifted to a platform. Again, Daryl throws a ball from a height of 6 ft with an initial vertical velocity of 24 ft/s. At the same time, Cheryl throws the ball she caught earlier. She throws her ball from a height of 24 ft with an initial vertical velocity of 6 ft/s so that it hits Daryl's ball. t = time, in seconds, since the balls were thrown h = height, in feet, above the ground Projectile motion formula: h = −16t2 + vt + h0 Which system of equations models this situation correctly?

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Answer:

h = -16t2 + 24t + 6

         h = -16t2 + 6t + 24

Step-by-step explanation:

i got it right

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Answer:

The answer is h=-16t^2+24t+6

Step-by-step explanation:

got it right!