Respuesta :

Answer:

(A)[tex]A=\dfrac12h(b_1+b_2)[/tex]

(D)[tex]b_1=\dfrac{2(A-\dfrac12 hb_2)}{h}[/tex]

Step-by-step explanation:

Given that:

[tex]A=\dfrac12h(b_1+b_2)[/tex]

[tex]2A=h(b_1+b_2)\\2A=hb_1+hb_2\\hb_1=2A-hb_2\\b_1=\dfrac{2A-hb_2}{h} \\b_1=\dfrac{2(A-\dfrac12 hb_2)}{h}[/tex]

Therefore, A and D are equivalent

Answer: A, C, D

(Edge)

I hope this helped!

Good luck <3

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