Answer:
[tex]D=2.25 m[/tex]
Explanation:
We can use the equation of a distance between to points:
[tex]D=\sqrt{(x_{1}-x_{0})^{2}+(y_{1}-y_{0})^{2}}[/tex]
Now, we know that the origin point (x₀,y₀) = (0,0) and the point (x₁,y₁) = (1.2,1.9)
[tex]D=\sqrt{(1.2-0)^{2}+(1.9-0)^{2}}[/tex]
[tex]D=2.25 m[/tex]
Therefore the distance of the fly will be D = 2.25 m from the corner.
I hope it helps you!
