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a cannonball is fired with a speed of 76 m/s from the top of a cliff. It strikes the plane below with a speed of 89 m/s. if we neglect air friction, how high is the cliff

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pawlossolomon

Answer:

we use the formula,

[tex]v {}^{2} = u {}^{2} + 2gh[/tex]

[tex]89 {}^{2} = 76 {}^{2} + 2(10)h[/tex]

[tex]h = (89 {}^{2} - 76 {}^{2} ) \div 20[/tex]

h= 107 m

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