Answer:
The depth of stream to the student is [tex]d_1 = 0.2932 \ m[/tex]
Explanation:
From the question we are told that
The actual depth of the stream is [tex]d = 39 \ cm = 0.39 \ m[/tex]
The refractive index of the water is [tex]n = 1.33[/tex]
Generally the apparent depth of the stream is mathematically represented as
[tex]d_1 = \frac{d}{1.33}[/tex]
substituting values
[tex]d_1 = \frac{ 0.39}{1.33}[/tex]
[tex]d_1 = 0.2932 \ m[/tex]
