Answer:
The answer is " [tex]122.88 \times 10^{-5}[/tex]"
Explanation:
In the given question some data is missing. so, the correct solution can be defined as follows:
Missing values:
[tex]k= 3.0 \times 10^{-5}\\\\NO_2 =6.4 \ mol / l \\\\CO= 4.1 mol / l \\\\NO= 5.2 mol / l \\\\CO_2= 1.3 mol / l\\[/tex]
Given equation:
[tex]NO_2(g) + CO(g) \longrightarrow NO(g) + CO_2(g)[/tex]
In the above equation, the rate is [tex]=k.[NO_2]^2[/tex] because the above given is the part of the second-order, which relates to [tex]NO_2[/tex]. In the zeros order the Carbon monoxide (CO) its reaction doesn't affect the rate.
Calculating the rate:
Rate [tex]=k.[NO_2]^2[/tex]
[tex]= 3.0 \times 10^{-5} \times 6.4^2\\\\=3.0 \times 10^{-5} \times 40.96\\\\= 122.88 \times 10^{-5}\\[/tex]
