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What is the slope of a line perpendicular to the line containing the points $(-1,2)$ and $(1,-2)$? Express your answer as a common fraction. Enter your answer

Respuesta :

Answer:

[tex]\frac{1}{2}[/tex]

Step-by-step explanation:

Calculate the slope of the line m using the slope formula

m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]

with (x₁, y₁ ) = (- 1, 2) and (x₂, y₂ ) = (1, - 2)

m = [tex]\frac{-2-2}{1+1}[/tex] = [tex]\frac{-4}{2}[/tex] = - 2

Given a line with slope m then the slope of a line perpendicular to it is

[tex]m_{perpendicular}[/tex] = - [tex]\frac{1}{m}[/tex] = - [tex]\frac{1}{-2}[/tex] = [tex]\frac{1}{2}[/tex]