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In the addition problem below, the digits B and C represent a number different from any of the other numbers shown (that is, not 1, 4, 5, 6, or 9. B5+C9=164

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shanelzheng240

B5 + C9 = 164

Split the numbers.

B0 +C0 +14 = 164.

B0 + C0 = 150

B + C = 15

B cannot be 1, 2, 3, 4, or 5 because that forces C to be a two digit number and C only represents 1 digit.

B cannot be 6 or 9 because they are present.

B can only be 7 or 8. C can also be 7 or 8.

Therefore, B = 7  and C = 8, OR B = 8 and C = 7.

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