Answer:
0.5 M NaOH solution
Explanation:
Initially, we have 0.25L or 250 mL of 8M NaOH solution
Which means that 1L of this solution would have 8 moles of NaOH
Moles present in 250 mL of solution:
Molarity * Volume( in L)
8 * 0.25 = 2 moles
There is 2 moles of NaOH in 0.25 L of the provided NaOH solution
More water is going to be added to this solution but the number of moles of NaOH will remain the same
now that the solution has a volume of 4L after adding the additional water, we have a 4L solution which contains 2 moles of NaOH
Molarity of the new solution:
Molarity = Number of moles in solution / Volume of solution
Molarity = 2 / 4
Molarity = 0.5 M
