Answer:
Step-by-step explanation:
Let R = Richard, T = Teo.
Richard and Teo have a combined age of 41. This means that if you add their ages together you get 41:
R + T = 41
We are also told Richard is 5 years older than twice Teo's age:
R = 2T + 5
You can substitute " R " into R + T = 41
R + T = 41
2T + 5 + T = 41
3T + 5 = 41
Subtract 5 from both sides
3T = 41 - 5
3T = 36
Divide both sides by 3 to find T.
T = 36/3 = 12
We know that R + T = 41, so
R = 41 - T
R = 41 - 12
R = 29
Answer:
Richard is 29 and Teo is 12
Step-by-step explanation:
let Teo's age be n then Richard is 2n + 5 ( 5 more than twice Teo's age )
Thus their combined ages are
n + 2n + 5 = 41 , that is
3n + 5 = 41 ( subtract 5 from both sides )
3n = 36 ( divide both sides by 3 )
n = 12
Then
Teo is 12 years old and Richard is 2(12) + 5 = 24 + 5 = 29 years old
