Answer:
5.4 feet
Step-by-step explanation:
Let the reference line [tex]A_0B_0[/tex] represents the sea level without any elevation.
At 1 P.M. the ocean surface was at an elevation of 2.2 feet along the line [tex]A_1B_1[/tex] in the figure and the surf shop was 8.2 feet above of this elevated ocean's surface along the line [tex]A_2B_2[/tex] in the figure.
Similarly, at 7 P.M. the ocean surface was at an elevation of -2.4 feet along the line [tex]A_3B_3[/tex] in the figure and the deck in the restaurant was 8.2 feet above of this elevated ocean's surface along the line [tex]A_4B_4[/tex] in the figure.
From the figure, the distance between the deck and the ocean's surface at 1 P.M.= The distance between the lines [tex]A_1B_1[/tex] and [tex]A_4B_4[/tex].
[tex]d= 10- (d_1+d_2)[/tex]
[tex]=10-(2.2+2.4)[/tex]
=5.4 feet
Hence, the distance between the deck and the ocean's surface at 1 P.M. is 5.4 feet.
The distance between the deck and the ocean surface at 1 P.M. is 5.4 feet.
This is a problem of relative and absolute distances. First, we determine the absolute elevation of the surf shop at 1 P.M.:
[tex]x_{1} = 8.2\,ft + 2.2\,ft[/tex]
[tex]x_{1} = 10.4\,ft[/tex]
Now we determine the absolute elevation of the deck at 7 P.M.:
[tex]x_{2} = 10\,ft - 2.4\,ft[/tex]
[tex]x_{2} = 7.6\,ft[/tex]
Lastly, we calculate the elevation of the deck relative to the ocean surface at 1 P.M.:
[tex]x' = 7.6\,ft - 2.2\,ft[/tex]
[tex]x' = 5.4\,ft[/tex]
The distance between the deck and the ocean surface at 1 P.M. is 5.4 feet.
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