Complete Question
An open rectangular box with length of 6 feet, width of 4 feet and height of 2.5 feet is to be painted on all exterior sides, including the bottom, with a special waterproof coating. Each gallon of this special coating covers 12 square feet of surface area and costs $36.00. The box is then to be filled with water that weighs approximately 62 pounds per cubic foot.
A. Find the cost of painting this open box.
B. Find the weight of the water in the filled box
Answer:
A
[tex]x = \$ 294[/tex]
B
[tex]z = 3720 \ pounds[/tex]
Step-by-step explanation:
From the question we are told that
The length is [tex]l = 6 \ ft[/tex]
The width is [tex]b = 4 \ ft[/tex]
The height is [tex]h = 2.5 \ ft[/tex]
Generally the total surface area of the open, rectangular box is mathematically represented as
[tex] T_ A = 2lb + 2lh + 2bh[/tex]
=> [tex] T_ A = 2(6 * 4) + 2(6 * 2.5) + 2(4 * 2.5)[/tex]
=> [tex] T_ A = 98 \ ft^2 [/tex]
From the question we are told that
$36.00 worth of paint covers [tex]12 ft^2[/tex]
So $x worth of paint covers [tex]98 \ ft^2[/tex]
=> [tex]x = \frac{98 * 36}{12}[/tex]
=> [tex]x = \$ 294[/tex]
Generally the volume of the open, rectangular box is mathematically represented as
[tex]V = l * b * h[/tex]
=> [tex]V = 6 * 4 * 2.5[/tex]
=> [tex]V = 60 \ ft^3 [/tex]
From the question we are told that
[tex]1 ft^3[/tex] weigh 62 pounds
[tex] 60 \ ft^3[/tex] weigh z pounds
=> [tex]z = \frac{60 * 62}{1}[/tex]
=> [tex]z = 3720 \ pounds[/tex]
