Answer:
Step-by-step explanation:
First you determine the variables x and y as:
x: the value for student tickets
y: the value for chaperone tickets.
Knowing that student tickets cost $ 2 more than companion tickets, it is represented by the equation:
x= y +2
On the other hand, there were 59 students and 6 companions. And the total cost of admission for the group was $ 508, that is to say that what all the students and the companions have paid adds up to $ 508. Expressed by an equation:
59x + 6y = 508
Then the system of equations to solve and thus obtain the price of a student ticket and the price of a companion ticket is:
[tex]\left \{ {{x=y+2} \atop {59x+6y=508}} \right.[/tex]
Solving for x, the price of a student ticket:
Rearranging the first equation,
y = x - 2
Replacing in the second equation and solving for x:
59*x + 6*(x -2)=508
59*x + 6*x -12=508
65*x -12=508
65*x= 508 +12
65*x= 520
[tex]x=\frac{520}{65}[/tex]
x=8
The cost of a student ticket is 8$
