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A mixture of xenon and oxygen gas is compressed from a volume of to a volume of , while the pressure is held constant at . Calculate the work done on the gas mixture. Round your answer to significant digits, and be sure it has the correct sign (positive or negative).

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sebassandin

Answer:

[tex]W=-6.99kJ[/tex]

Explanation:

Hello,

In this case, since the work at constant pressure is computed via:

[tex]W=P\Delta V=P(V_2-V_1)[/tex]

For an initial volume of 99.0 L and a final one of 98.0 L, accounting for a compression process at a pressure of 69.0 atm, we obtain a negative work, meaning that work is done on the gas, according to the first law of thermodynamics:

[tex]W=69.0atm(98.0L-99.0L)\\\\W=-69atm*L[/tex]

However, the work in kJ with three significant figures because the initial data have all three significant figures, is:

[tex]W=-69.0atm*L*\frac{101.325kPa}{1atm}*\frac{1m^3}{1000L} \\\\W=-6.99kJ[/tex]

Best regards.

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