contestada

If the neutron microscopic absorption cross section of boron at 0.0253 eV is 3847 barns, what would it be at 0.1 eV? [ Ans. 1935 b ]

Respuesta :

Answer:

The correct answer will be "1935 barns".

Explanation:

The given values are:

[tex]E_{1}[/tex] = 0.0253 eV

[tex]E_{2}[/tex] = 0.1 eV

[tex]\sigma_{2}[/tex] = 3847 barns

Now,

⇒  [tex]\frac{\sigma_{1}}{\sigma_{2}} = \frac{E_{1}}{E_{2}}[/tex]

then,

⇒  [tex]\sigma_{1}=\sigma_{2}\sqrt{\frac{E_{1}}{E_{2}}[/tex]

On substituting the given values, we get

⇒       [tex]=3847\times \sqrt{\frac{0.0253}{0.1} }[/tex]

⇒       [tex]=1935 \ barns[/tex]