Answer:
The value is [tex]V_2 = 0.246 \ m^3/h[/tex]
Explanation:
From the question we are told that
The temperature at which the gas enters the compressor is
[tex]T_i = 298 \ K[/tex]
The pressure at which the gas enters the compressor is
[tex]P_I = 1.0 \ atm[/tex]
The volumetric rate at which the gas enters the compressor is
[tex]V = 127 m^3/h[/tex]
The temperature to which the gas is compressed to is
[tex]T_f = 358 \ K[/tex]
The pressure to which the gas is compressed to is
[tex]P_f= 1000 \ atm[/tex]
Generally the volumetric flow rate of compressed oxygen is evaluated from the compressibility-factor equation of state as
[tex]V_2 = V_1 *\frac{z_2}{z_1} * \frac{T_2}{T_1} * \frac{P_1}{P_2}[/tex]
Here [tex]z_1[/tex] is the inflow compressibility factor with value [tex]z_1 = 1[/tex]
Here [tex]z_1[/tex] is the outflow compressibility factor with value [tex]z_2 = 1.61[/tex]
So
[tex]V_2 = 127*\frac{1.61}{1} * \frac{358}{298} * \frac{1}{1000}[/tex]
[tex]V_2 = 0.246 \ m^3/h[/tex]
