Answer:
A reflection over a given line leaves the distance between each point and the line invariant.
Some basic rules are:
for a point (x, y)
- a reflection over x = 0, leaves our point as (-x, y)
- a reflection over y = 0, leaves our point as (x, -y)
Now, in the image, we can see that in one triangle the base faces down, and in the other the base faces up. Then we must start with a reflection over the line y= 0.
And now our triangle will be in the fourth quadrant, and triangle B is in the 3rd quadrant, then we need to do a reflection over the line x = 0.
(is the same as doing first a reflection over the line x= 0 and then other over the line y = 0)
Now, triangle A is in quadrant 1 and triangle B is in quadrant 3, so we can do a reflection over a line that divides those quadrants, that line is y = -x.
Then the correct options are:
A reflection over the line y = -x
A reflection over the line x = 0 followed by a reflection over the line y = 0
