Answer:
Q = 84.6 kJ
Explanation:
Given that,
The latent heat of vaporization for ethanol, L = 846 J/g
Mass, m = 100 g
We need to find the thermal energy required to boil away the ethanol. It can be given by the formula as follows :
Q=mL
Q = 100 g × 846 J/g
Q = 84600 J
or
Q = 84.6 kJ
Hence, thermal energy is 84.6 kJ.
