Respuesta :

emberedwards737

Answer:

graph{y=4x+1 [-10, 10, -5, 5]}

Step-by-step explanation:

Since the equation is linear/straight in the form

y = mx + c, you can determine the slope/gradient (m) and y-intercept (c).

m = 4

c = 1

To graph this equation, you'll need to find 2 points on the line and join them together. We know one of the points is (0, 1) as the y-intercept is 1.

You can find another point by substituting an arbitrary number into

x or y in the equation. In this example, I'll substitute 1 into x to find the y coordinate where the x coordinate is 1.

y = 4 (1) + 1

y = 4 + 1

y = 5

So, the second point would be (1, 5).

If you join the points (0, 1) and (1, 5) on a graph, this would be the line of the equation.

hope this helps!

abidemiokin

The coordinates for the point for this equation  [tex]y - 4 = -\frac{1}{3} (x-7),[/tex] is at (7, 4)

The standard form of the equation in point-slope form is expressed as:

[tex]y-y_0=m(x-x_0)\\[/tex]

m is the slope of the line

[tex](x_0, y_0)[/tex] is any point on the line

Given the equation [tex]y - 4 = -\frac{1}{3} (x-7),[/tex]

Compare the original equation with the given equation to get the coordinate for the point [tex](x_0, y_0)[/tex].

On comparison:

[tex]-x_0=-7\\x_0=7\\-y_0=-4\\y_0=4[/tex]

Hence the coordinates for the point is at (7, 4)

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