The graph of the function h(t)=-16t^2+39 is graph (b)
The equation of the function is given as:
h(t)=-16t^2+39
The above function is a quadratic function that as a y-intercept of 39.
This is shown as follows:
h(0)=-16 * 0^2+39
Evaluate the exponent
h(0)=-16 * 0+39
Evaluate the product
h(0)=0+39
Evaluate the sum
h(0)= 39
Hence, the graph of the function h(t)=-16t^2+39 is graph (b)
Read more about quadratic functions at:
https://brainly.com/question/1214333
