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Calculate the concentration of sodium hydroxide solution obtained when:

1.(a) 2 ml of 0.1 mol/l NaOH is added to 25 ml of water

(b) 10 g of NaOH are added to 50 ml of water

Respuesta :

Bowmastersai

Answer:

moles Ca(OH)2 ---> (0.10 mol/L) (0.060 mL) = 0.0060 mol

moles HNO3 ---> (0.10 mol/L) (0.050 mL) = 0.0050 mol

Ca(OH)2 + 2HNO3 ---> Ca(NO3)2 + 2H2O

Two HNO3 are required to neutralize one Ca(OH)2, so only 0.0025 mol of Ca(OH)2 will be neutralized.

0.0060 mol minus 0.0025 mol = 0.0035 mol of Ca(OH)2 remaining

Ca(OH)2 and H2SO4 react in a 1 to 1 molar ratio, so 0.0035 mol of H2SO4 is required.

volume H2SO4 ---> 0.0035 mol / 0.10 mol/L = 0.035 L = 35.0 mL

Explanation: