When placed in 1 L of water, which of the following combinations would give a buffer solution?1. 0.5 mol HClO and 0.5 mol NaClO2. 0.5 mol HBr and 0.5 mol NaF3. 0.5 mol HBr and 1.0 mol NaF4. 0.5 mol HBr and 1.0 mol NaOH

Respuesta :

Answer:

3.8 g Fe * 1 mol Fe/55.85 g Fe (molar mass) = .0680 mol Fe

.0680 mol Fe * 2 mol HBr/1 mol Fe (found in formula Fe+2HBr=>FeBr2+H2)=.136 mol HBr

.136 mol HBr*80.912 g HBr/1 mol HBr=11.004 g HBr (or 11 using 2 sig figs)

And the mass of H2 that is produced is 0.14 g

Explanation: